BaseBall Question (Momentum & Impulse in 2 dimensions)

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Homework Help Overview

The discussion revolves around a baseball physics problem involving momentum and impulse in two dimensions. The original poster presents a scenario where a baseball is struck by a bat, and they are tasked with finding the impulse experienced by the ball and the average net force acting on it.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster expresses confusion between the concepts of impulse and net force, questioning their calculations and the assignment of positive and negative directions. They attempt to clarify their understanding of the relationships between impulse, momentum, and force.

Discussion Status

Participants are engaged in clarifying the definitions and relationships between impulse and momentum. Some have provided insights into the vector nature of momentum and the concept of force as the rate of change of momentum. The original poster seeks further guidance on calculating impulse and net force, indicating an ongoing exploration of the problem.

Contextual Notes

The original poster mentions confusion regarding the assignment of positive and negative directions, which impacts their calculations. They also note that changing these directions can lead to significant variations in their results.

HarleyM
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Homework Statement


a baseball with a mass of 0.152 kg is moving horizontally at 32.0 m/s [E] when it is struck by a bat for 0.00200 seconds. The velocity of the ball just after the collision is 52.0 m/s [W 20 N]

a) Find the impulse experienced by the ball
b) find the average net force of the ball


Homework Equations


FnetΔT=M(V2-V1)


The Attempt at a Solution



Im confused between impulse and net force first of all.. I think I calculated both but I am unsure, Also I am unsure about which directions I should set at positive and negative,

I set East and North as positive

Fnetx(0.002)=(0.152)((-)52cos20-32) ( 52 is negative in this case since movement in x direction is towards W?)

Fnet= - 6145.36, negative so [W]

Fnety(0.002)=(0.152)(52sin20-0) ( 52 is positive here since i set north to = positive)

Fnet=1351.28 N

I make the triangle with my components and solve for hypotenuse through pythag. = 6292.17 ∅= W 12.4° N

IS the hypotenuse equal to net force and the components equal to impulse?
DO my directions and calculations look correct?

Thank you everyone who takes the time to read this and make an attempt at helping me !
 
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First of all: Impulse is momentum. Momentum is a vector quantity
Force is rate of change of momentum ie change in momentum (or impulse) per second
 
I guess you can't help with regards to math and setting positive and negative directions?

That seems to be where most of my confusion is coming from.. Thank you for clearing up momentum and force for me though!

If I change my directions for certain things the numbers can change drastically so its quite confusing..

thanks again!
 
BUMP

I didn't get full marks for this question,

Where exactly do I calculate impulse..


Is it

FnetΔt=M(V1-V2)
FnetΔt=answer for impulse ?

and net force is equal to Fnet= answer for net force?
 
Would impulse in this case be equal to

ΔPx=(Fnetx)(Δt)
ΔPy=(Fnety)(Δt)

SO I have an impulse in the x and y dimensions?

Can someone please shed some light for me!
 

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