Two objects are at rest on a frictionless surface. m1 > m2
(1) When a constant force is applied to object 1, it accelerates through a distance d in a straight line. The force is removed from object 1 and is applied to object 2. At the moment when object 2 has accelerated through the same distance d, which statements are true?
(a) p1 < p2 (b) p1 = p2 (c) p1 > p2 (d) K1 < K2 (e) K1 = K2 (f) K1 > K2
(2) When a force is applied to object 1, it accelerates for a time interval delta t. the force is removed from object 1 and is applied to object 2. From the same list of choices, which statements are true after object 2 has accelerated for the same time interval delta t?
delta p = I
I = integral of Ti to Tf (F * dt)
dp = F * dt
p = mv
The Attempt at a Solution
The answers for 1 is c and e ; for 2 is b and d
First, constant force means constant acceleration. F = ma, and F = d(mv) / dt = dp / dt
Since m1 > m2, this is why c is true for 1.
K = mv^2 / 2. If we have the same acceleration, then how do we determine which one has a greater velocity? The book cited W = Fd which is great, but I can be dumb and not remember this fact. So let's discuss the velocity for now.
For the second problem, the book use impluse and state their impluse are the same, so p1 = p2. Let's go back to our first problem.
How do we find the impluse for our first problem? Can't the impluse be the same even when the delta time is not the same?
For second problem:
So F is not constant, a is not constant either. again, how do we know the velocity?
I have a hard time applying things.