- #1
Jahnavi
- 848
- 102
Click For Summary
SUMMARY
The discussion centers on the concept of impulse in physics, specifically in relation to a position-time graph indicating uniform motion. Participants clarify that impulse is defined as the change in momentum, expressed mathematically as m∆v, where ∆v represents the change in velocity. Since the velocity remains constant between t=0 and t=2 seconds, the impulse at t=2 seconds is zero, as there is no change in momentum. The conversation emphasizes the distinction between impulse and momentum, confirming that impulse is indeed the change in momentum.
PREREQUISITES- Understanding of basic physics concepts, particularly momentum and impulse.
- Familiarity with the equations of motion, specifically m∆v and F=m(dv/dt).
- Knowledge of uniform motion and its implications on velocity.
- Ability to interpret position-time graphs in the context of kinematics.
- Study the relationship between impulse and momentum in detail.
- Learn about the implications of uniform motion on force and impulse calculations.
- Explore advanced kinematics topics, including acceleration and its effects on impulse.
- Review real-world applications of impulse in collision and impact scenarios.
Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of impulse and momentum in motion analysis.
- #2
stockzahn
Homework Helper
Gold Member
- 498
- 137
Jahnavi said:
Unfortunately not. The impulse is the product of mass and velocity. ##m\Delta v## is the change in momentum ##\Delta p##, from which you can calculate the acting force, if you know the time of the velocity change (##F=m\frac{dv}{dt}##).
- #3
Jahnavi
- 848
- 102
stockzahn said:
Sorry . This is conceptually wrong .
Product of mass and velocity is momentum . Impulse is change in momentum .
- #4
- 22,820
- 14,877
This is not the question. The question is what the impulse given at t = 2 s is.Jahnavi said:
- #5
- 22,820
- 14,877
Jahnavi said:
No it is not.
Which means that the change in momentum (with constant mass) is the mass multiplied by the change in velocity, i.e., ##\Delta p = m\, \Delta v##, just as stated in #2.
- #6
Jahnavi
- 848
- 102
Orodruin said:
You are right . Thanks !
- #7
stockzahn
Homework Helper
Gold Member
- 498
- 137
Jahnavi said:
Yes you are right, I'm sorry - language problem.
- #8
Jahnavi
- 848
- 102
Orodruin said:
It is .
Please read post#2 again . I objected to the definition of impulse .
- #9
Jahnavi
- 848
- 102
stockzahn said:
No problem
Similar threads
- · Replies 6 ·
- · Replies 1 ·
- · Replies 2 ·
- · Replies 14 ·
- · Replies 7 ·
- · Replies 24 ·
- · Replies 1 ·
- · Replies 8 ·