Impulse-Momentum Theorem and acceleration

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SUMMARY

The discussion focuses on applying the Impulse-Momentum Theorem to calculate the final velocity and acceleration of a 3.00 kg object initially moving at 7.00 j m/s under a force of 12.0 i N for 5 seconds. The Impulse-Momentum Theorem states that the impulse (force multiplied by time) equals the change in momentum. Participants confirmed that using the equation F*Δt = m*Δv allows for the calculation of the object's final velocity and acceleration, with the latter being derived from both the change in velocity and the force divided by mass.

PREREQUISITES
  • Understanding of the Impulse-Momentum Theorem
  • Basic knowledge of Newton's Second Law (F = m*a)
  • Familiarity with momentum and its calculation (Δp = m*Δv)
  • Ability to manipulate equations involving force, mass, and acceleration
NEXT STEPS
  • Study the Impulse-Momentum Theorem in detail
  • Learn how to derive acceleration using a = (vf - vi) / Δt
  • Explore practical applications of Newton's Second Law in various scenarios
  • Practice problems involving force, mass, and acceleration calculations
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of motion and forces.

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Impulse-Momentum Theorem...

Homework Statement


So here's the problem:
a 3.00 kg object has velocity 7.00 j m/s. Then, a total force of 12.0i N acts on the object for 5 seconds.
A.Calculate the object's final velocity using the impulse momentum theorem.
b. calc its acceleration from a = (vf - vi) / delta t.
c. calculate its acceleration from a = F/m

Homework Equations


<given in question>

I really don't know what to use for impulse-momentum theorem in a? Any and all help is appreciated...
 
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Welcome to PF.

F = m*a = m*Δv/Δt

F*Δt = m*Δv = Δp

So in a, you have F and Δt. That gives you Δp
 

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