In a solution of 0.10 M H2SO4, the ions present in order of decreasing order.

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SUMMARY

In a 0.10 M H2SO4 solution, the predominant ions present in order of decreasing concentration are [H3O+] > [HSO4-] > [SO4-2] > [OH-]. The dissociation of sulfuric acid (H2SO4) in water leads to the formation of hydronium ions (H3O+) and hydrogen sulfate ions (HSO4-). Due to the strong acid nature of H2SO4, the first dissociation is complete, resulting in a significant concentration of H3O+ and HSO4-. The second dissociation to form sulfate ions (SO4-2) is less significant in this concentration.

PREREQUISITES
  • Understanding of strong acid dissociation, specifically H2SO4.
  • Knowledge of hydronium ion concentration in aqueous solutions.
  • Familiarity with ICE tables for equilibrium calculations.
  • Basic principles of acid-base chemistry.
NEXT STEPS
  • Study the dissociation constants (Ka) for H2SO4 and its implications on ion concentrations.
  • Learn about the behavior of strong acids in water and their impact on pH levels.
  • Explore the concept of ionic strength in solutions and its effect on ion activity.
  • Investigate the equilibrium expressions for weak acids and how they differ from strong acids.
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Chemistry students, educators, and anyone studying acid-base equilibria and the behavior of strong acids in aqueous solutions.

alliereid
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Homework Statement


The answer is [ H3O+ ] > [HSO4-]>[SO4-2]>[OH-], but I do not understand how they got it?


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The Attempt at a Solution


First I tried to put H2SO4 into water and got HSO4-. Then I tried to make an ice table, but it didn't work out since Ka for H2SO4 = very large?

H2SO4 + H2O <====> HSO4- + H3O+
 
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It is a problem in logic. You don't need to do an exact calculation.
 

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