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In comparing different renormalization procedures why do we care about symmetry?

  1. Jan 10, 2012 #1
    Why do we care about Lorentz or gauge invariance if we're going to remove the cutoff at the end. our physical answers are independent of the procedure,, why do we care about preserving the symmetry "during" the calculation?

    Thanks for your time!
     
  2. jcsd
  3. Jan 10, 2012 #2
    In fact we don't care!

    The only important thing is that somebody (= 't Hooft) as proved that different procedures give the same results, and there exists a procedure that preserves those symmetries.
    So we know that the result has Lorentz and gauge symmetries and you can chose any procedure to make your calculation
     
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