In Desperate Need of Help Analysis Homework

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Homework Help Overview

The discussion revolves around a functional analysis problem involving a function f: R→R that satisfies the property f(u+v)=f(u)+f(v) for all real numbers u and v. Participants are tasked with proving specific properties of the function based on its behavior at rational and irrational numbers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of the functional equation, with some suggesting the use of the Mean Value Theorem and continuity definitions. Others discuss specific values of the function, such as f(1), f(1/2), and f(2), to build their arguments. There are questions about the validity of certain steps in the proofs and the clarity of the problem statement.

Discussion Status

The conversation is ongoing, with various participants providing hints and suggestions. Some have offered specific approaches to proving the properties of f, while others express confusion and seek clarification on the steps involved. There is a mix of interpretations being explored, particularly regarding the application of continuity and the behavior of f at rational versus irrational numbers.

Contextual Notes

Participants mention a lack of understanding of the problem's requirements, with some expressing difficulty in writing proofs. The urgency of the assignment's deadline adds pressure to the discussion.

Janez25
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Homework Statement


Let f: R→R have the property that for every u and v in R.
f(u+v)=f(u)+f(v)
(a) Prove: If f(1)=m, then f(x)=mx for all rational numbers x.
(b) Prove: If f is continuous, then f(x)=mx for all x ∈ R.

Homework Equations


The Attempt at a Solution


I am really lost on this problem. We have kind of rushed through the topic of continuity, but I believe I should use the MVT on part (a) and the definition of continuity on part (b).
 
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For part a, here is a hint:

Notice that f(1) = f(1/2 + 1/2) so... Also, f(2) = f(1 + 1) so...

For part b, here is a hint: once you have shown part a, you will know that f(x) = mx at all values of x that are rational. Now, let w be irrational. Then, you can find rationals "near" w, in fact on any open interval around w there are rationals in that interval. Use part a and continuity to conclude that f(w) = mw.
 
How do you know that f(1) = f( 1/2 + 1/2) and f(2) = f( 1+1)? I am really bad at writing proofs.
 
Janez25 said:
How do you know that f(1) = f( 1/2 + 1/2) and f(2) = f( 1+1)? I am really bad at writing proofs.

erm :redface: … because 1 = 1/2 + 1/2 and 2 = 1 + 1 …

that's all Russell Berty :smile: is saying! :wink:
 
Thanks! I feel so special now. :blushing:
 
tiny-tim said:
erm :redface: … because 1 = 1/2 + 1/2 and 2 = 1 + 1 …

that's all Russell Berty :smile: is saying! :wink:

My professor suggested using f(3/2) = f(1+1/2) = f(1) + f(1/2) = f(1/2 + 1/2) + f(1/2) = f(1/2) + f(1/2) + f(1/2) = 3f(1/2).
I guess I am having so much difficulty with this problem because I do not understand what it is really asking me to prove. I really need this broken down. It takes me a little longer than others I guess. :confused:
 
You want to show that f(x) = mx for rational x, and then from the continuity of f, show that this is true for irrational x too.

If x is rational, we can write it in the form p/q where both p and q are integers. Now we have:

f(p/q) = f(1/q) + f(1/q) + ... + f(1/q) (p times) = pf(1/q)

Prove that f(1/q) = m/q and then you're done with rational x. Use f's continuity to extend it to irrational x too.
 
Janez25 said:
My professor suggested using f(3/2) = f(1+1/2) = f(1) + f(1/2) = f(1/2 + 1/2) + f(1/2) = f(1/2) + f(1/2) + f(1/2) = 3f(1/2).

I think your professor is being rather obscure. :frown:

Let's start again …

f(1) = m …

ok: then what's f(1 + 1 + … 1) = f(n) for a whole number n ?

and what's f(1/n + 1/n + … 1/n) ? :smile:
 
Is the first part mf(n)? Is the second part mf(1/n)?
 
  • #10
Janez25 said:
Is the first part mf(n)? …

oooh, that doesn't even make sense :cry:

Be systematic …

write it out step by step

f(1) = m,

so f(n) = f(1 + 1 + … 1) = f(1) + f(1) + … + f(1) = … ? :smile:

And f(1/n) = … ?
 
  • #11
Ok, the first part is f(1)=pm, and the second part is f(1/n)=p(m/n). I guess?

I am starting to feel about this problem the way my Algebra II students feel about their homework assignments. It is really giving me grief. I know the proof is probably very simple, but the more I think about the problem the more confused I become:confused:
 
  • #12
No, f(1) = m.

Now if n is a positive integer, then f(n) = f(1 + 1 + 1 + ... + 1) n amount of times = f(1) + f(1) + ... + f(1) n amount of times = ??

Also, m = f(1) = f(1/n + 1/n + ... + 1/n) n amount of times = f(1/n) + f(1/n) + ... + f(1/n) n amount of times = ??
 
  • #13
Ok, does the first part = mn, and the second part = m/n?

My professor also mentioned that for part (a) we should also include the proof that f(a/b)=af(1/b).
For that part of (a) I have f(a/b)=f(a+1/b)=f(a)+f(1/b)=? This is where I got lost.
 
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  • #14
There you go. You've showed that f(1/q) = m/q. Can you show what f(p/q) is equal to? And show your work next time please :)
 
  • #15
Ok, f(p/q)=f(p+1/q)=f(p)+f(1/q)=f(1/q+1/q)+f(1/q)=?
 
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  • #16
f(p/q) is NOT equal to f(p + 1/q). W

e'll use a/b instead of p/q. To show that f(a/b) = af(1/b):

f(a/b) = f(1/b + 1/b + ... + 1/b) a amount of times = f(1/b) + ... + f(1/b) a amount of times = af(1/b). Can you now conclude what f(a/b) is equal to?
 
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  • #17
So, f(a/b)=ma/b. I hope this is right, because this assignment is due at 6:35p.m. I will try to finish on my own. Thanks for everyone's help!
 

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