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Q1. Venn diagrams.

[PLAIN]http://img826.imageshack.us/img826/3194/23872542.jpg

Find:

a) Pr(A∩B)

b) Pr(AUB)

c) Pr(AUB')

a) this is easy, Pr(A∩B)=3/33=1/11

b) Pr(AUB)=(10+3+12)/33=25/33

c) this is the one I am not 100% sure on. I looked at the set of A and the set of B' seperately then took the intersection, I got Pr(AUB') = (10+3+8)/33 = 21/33

Q2. conditional pr.

Out of a standard deck of 52 cards, 5 cards are chosen at random. What is the probability that the ace of spades is chosen given at least one ace is chosen.

so I'm looking at conditional probability and the formula Pr(A|B) = Pr(A∩B)/Pr(B), where Pr(A) is probability of choosing ace of spades, and Pr(B) is probability of choosing at least one ace.

Pr(B) is simply 1-Pr(no aces).

Is this the right way to go about this question? If so, how do I find pr(no aces) and Pr(A∩B)?

[PLAIN]http://img826.imageshack.us/img826/3194/23872542.jpg

Find:

a) Pr(A∩B)

b) Pr(AUB)

c) Pr(AUB')

a) this is easy, Pr(A∩B)=3/33=1/11

b) Pr(AUB)=(10+3+12)/33=25/33

c) this is the one I am not 100% sure on. I looked at the set of A and the set of B' seperately then took the intersection, I got Pr(AUB') = (10+3+8)/33 = 21/33

Q2. conditional pr.

Out of a standard deck of 52 cards, 5 cards are chosen at random. What is the probability that the ace of spades is chosen given at least one ace is chosen.

so I'm looking at conditional probability and the formula Pr(A|B) = Pr(A∩B)/Pr(B), where Pr(A) is probability of choosing ace of spades, and Pr(B) is probability of choosing at least one ace.

Pr(B) is simply 1-Pr(no aces).

Is this the right way to go about this question? If so, how do I find pr(no aces) and Pr(A∩B)?

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