In probability formula, what does n represent?

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SUMMARY

In the binomial probability formula P_N(n) = N!/(n!(N-N)!) (p^n)(q^(N-n)), the variable n represents the number of successful outcomes in N independent trials. Each trial has a success probability of p and a failure probability of q = 1 - p. The formula calculates the probability of achieving exactly n successes out of N trials, applicable in scenarios such as coin flips, dice throws, and multiple-choice exams.

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In the formula,

PN(n) = N!/(n!(N-N)!) (p^n)(q^(N-n))

N represents the number of elements, but what exactly does little n represent?

Thanks for any help!
 
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The formula you gave,
P_N(n) = \frac{N!}{n! (N - n)!} p^n q^{N - n}
is the probability of n successes after N trials in a binomial distribution.

That is, you run N trials and for each of them the chance for "success" is p, and the chance for "failure" is q = 1 - p. The formula above gives the probability that out of the N trials, you get 0 \le n \le N "successes".

Some examples: if you flip a coin N times, and define "success" as "heads comes up" (with p = 1/2) then PN(n) is the probability of finding exactly n heads and N - n tails in N flips.

If you throw a die N times, and define "success" as "six comes up" (with p = 1/6) then PN(n) is the probability of getting exactly n sixes and N - n other values in N throws.

If a multiple-choice exam has N questions, and you randomly select one of the four answers for each of them then "success" can be "question is answered correctly" (with p = 1/4) and PN(n) is the probability of getting exactly n questions right and N - n wrong.
 
This helps so much! Thank you!
 

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