In the integral , use the power-series

  • Thread starter Thread starter Jamin2112
  • Start date Start date
  • Tags Tags
    Integral
Click For Summary
SUMMARY

The discussion focuses on evaluating the integral involving the power series expansion of the logarithmic function log(1+x). The correct power series expansion is identified as log(1+x) = x - x²/2 + x³/3 - ... . The primary challenge discussed is how to raise this series to the power of q, particularly as x approaches zero, where the lower limit presents a problem. The conclusion emphasizes that for small values of x, log(1+x) can be approximated as x, simplifying the process of raising it to the q power.

PREREQUISITES
  • Understanding of power series expansions
  • Familiarity with logarithmic functions
  • Knowledge of integral calculus, specifically integrals of the second type
  • Basic algebraic manipulation of series
NEXT STEPS
  • Research the properties of power series and their convergence
  • Learn about the application of Taylor series in calculus
  • Explore techniques for evaluating integrals with singularities
  • Study the implications of raising series to a power in calculus
USEFUL FOR

Students and educators in calculus, particularly those focusing on integrals and series expansions, as well as mathematicians interested in the behavior of logarithmic functions near singularities.

Jamin2112
Messages
973
Reaction score
12

Homework Statement



I wrote it on Word for increased clarity.

screen-capture-30.png


Homework Equations



This is in the chapter where we learned about integrals of the "second" type, ones that have a problem as x approaches the upper or lower limit.

The Attempt at a Solution



I know that the power series expansion for log(1+x) is 1 - x2/2 + x3/3 - x4/4 + ... .

But raising that to the q power ... How is that done?
 
Physics news on Phys.org
Correct that to log(1+x)=x-x^2/2+x^3/3+... And the only problem is at the lower limit, right? So you can take x to be very close to zero. I'd just say log(1+x)~x. Raising that to the q power should be easy.
 
Last edited:

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
Replies
8
Views
3K
Replies
4
Views
3K
Replies
6
Views
2K
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K