In which case temperature increase is highest

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SUMMARY

The highest temperature increase when mixing a strong acid and a base of 1 N concentration occurs in option B, which involves 40ml of acid and 40ml of alkali. This conclusion is derived from the Law of Equivalents, where the volumes of the reactants are equal, leading to maximum heat release. The equation q=mcΔT is relevant for calculating the temperature change, where q represents heat, m is mass, and c is specific heat capacity. Understanding these principles is crucial for accurately predicting temperature changes in acid-base reactions.

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  • Basic concepts of molarity and normality in solutions
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utkarshakash
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Homework Statement


In which case of mixing of a strong acid and a base each of 1 N concentration, temperature increase is highest.

A)20ml acid-30ml alkali
B)40ml acid-40ml alkali
C)25ml acid-25ml alkali
D)35ml acid-15ml alkali


Homework Equations


Law of Equivalents

The Attempt at a Solution


Using the law of equivalents I have
[itex]N_{1}V_{1}=N_{2}V_{2}[/itex]
Since both are 1 N
[itex]∴V_{1}=V_{2}[/itex]
So I am now left with options B and C but I don't have any clues how to differentiate between the two. Speaking in layman's term in option B the volume is more so temperature increase will be highest(Fortunately this is correct answer:wink:) but I need a scientific reasoning for this.
 
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B is not the only correct answer.

q=mcΔT, solve for ΔT, see if it helps.
 
Borek said:
B is not the only correct answer.

q=mcΔT, solve for ΔT, see if it helps.

I don't know q,m and c. How can I solve it?
 

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