- #1

anton717

- 9

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## Homework Statement

Photogate 1 is at the 25.2 cm mark, and photogate 2 is at the 66.4 cm mark along the track, Assume

* The bottom of the track is at

*U*= 0 J (potential energy is zero).

* The total mass of the cart is 214 g.

* The track is totally frictionless

Suppose the cart is released at rest at some point above photogate 2 (the higher point on the track). If the cart passes through photogate 2 at speed 0.497 m/s, at what speed will the cart pass through photogate 1?

*v*1 = ____________ m/s

## Homework Equations

I am thinking about mgh+ 1/2 (mv^2) = mgh' + 1/2 (mv'^2)

also vf^2=vi^2+2ad might be helpful?

## The Attempt at a Solution

I went ahead and did PEi+KEi=PEf+KEf

and got a wrong answer for Vf (which is v1)? ( I got something like vf= 0.998 )

What have I done wrong? Did I not consider the acceleration?

Well, I tried that way a=gsin(x), I found the a to be 1.143 m/s^2 and after that I am a bit confused with 2 different heights and lack of info to find Vf (v1)... (may be I m not getting it)

Would be awesome if someone would help me with the concept or answer.

Thanks,