Inclined plane problem, weight of subject

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Homework Help Overview

The problem involves a man standing on a scale placed on a frictionless inclined plane, specifically a wedge. The inquiry centers around determining the weight that the scale will measure, given the man's mass and the angle of the incline.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the effects of the inclined plane on the weight measurement, with some considering the implications of the wedge's angle and the absence of friction. Questions arise regarding how the setup alters the expected readings on the scale compared to a flat surface.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants have offered insights into the forces at play, while others express uncertainty about the correct approach to analyze the situation. No consensus has been reached yet.

Contextual Notes

Participants are navigating assumptions related to the motion of the man and the scale, including scenarios where the block may be sliding or stationary. The lack of explicit details about the acceleration and forces involved adds complexity to the discussion.

ellano
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Homework Statement



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This man has mass 'm' and the angle of the plane is 'x'. The inclined plane is frictionless. He is standing on a scale which is placed on top of the blue wedge, what weight will the scale measure?

Homework Equations



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The Attempt at a Solution



If the man was standing on a regular block, I would say his weight would be equal to

mgcos(x)

But I am confused as to whether standing on a wedge would change things.

Thanks for trying to help!
 
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The block is sliding with an acceleration gsin(theta). Find its vertical component. When the block is falling freely, the reaction or reading in scale will be zero. If it is falling vertically with some acceleration, what will be the reaction?
 
Well, if the man was on a block like the following:

xd9obt.jpg



And that ramp was inclined at angle theta, I would say that the downwards acceleration would be gcos(theta), and so the scale would read mgcos(theta).

But, in the problem from the first post with the blue wedge, the man and the scale are actually standing on a flat surface.

So, in that case, I don't know how to draw the vectors in order to figure out what force is being put on the scale.
 
In the first case if the block is stationary, the scale will read his weight. Since it is sliding, the new weight will be m(g-a). In non inertial frame, pseudo force is in the opposite direction to the actual force.
 

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