Incremental rotary encoder motor help

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
AC130
Messages
5
Reaction score
0

Homework Statement


Hi please see the image that I have attached. The text colored in red is the data I need to calculate.

Homework Equations

The Attempt at a Solution


The encoder has 128 counts per revolution
So to calculate corresponding angle change this I what I did
I divided encoder count in decimal number by 128 which gave the number of revolutions, I then multiplied it by 360 to find the angle change

So for example I did
6350/128 = 49.61 revolutions
49.61 * 360 = 17859.34 degrees

Is this method right?

To calculate no load speed RPM, I divided the revolutions by (time*60) to get it to RPM

So for the 6350 encoder count which gave 49.61 revolutions

I did

49.64/(5.25*60) = 0.1575 RPM

Is this RPM calculation right?

For me it looks as if the RPM is well below and so I must have made a mistake somewhere but I don't know specifically where
 

Attachments

  • encoder motor.JPG
    encoder motor.JPG
    35 KB · Views: 453
Physics news on Phys.org
AC130 said:
So for example I did
6350/128 = 49.61 revolutions
49.61 * 360 = 17859.34 degrees
That's correct.

To calculate the speed, you must know the sample frequency. Say it is 1Hz. Then you will have 6350 counts per second.
Convert to RPM. ( 128 counts per rev, 60 sec/min ).

The result is close to 3000 RPM.

If the sample frequency were 2Hz, the motor speed would be the double ( ≈ 6000 RPM ).
 
Last edited:
Hesch said:
That's correct.

To calculate the speed, you must know the sample frequency. Say it is 1Hz. Then you will have 6350 counts per second.
Convert to RPM. ( 128 counts per rev, 60 sec/min ).

The result is close to 3000 RPM.

If the sample frequency were 2Hz, the motor speed would be the double ( ≈ 6000 RPM ).

Hi can you please tell me where RPM came from?
I know that it took 5.25 sec for the angle change and so frequency would be 1/T = 1/5.25 = 0.1905Hz

But I don't really know how to find RPM
 
AC130 said:
So for the 6350 encoder count which gave 49.61 revolutions
AC130 said:
I know that it took 5.25 sec for the angle change
So 49.61 rev. within 5.25 sec, which gives 9.449 rev./sec ≈ 567 rev/min. = 567 RPM. ( 1 min = 60 sec ).

The RPM's in #2 is just an example, not knowing your mentioned 5.25 sec.
 
Ok thanks I understand it now