MHB Indefinite integral in division form

Click For Summary
SUMMARY

The discussion revolves around solving the indefinite integral $$\int \frac{2}{x - b \frac{x^{m - n + 1}}{(-x + 1)^m}} \, dx$$. The user attempted to simplify the integral using algebraic manipulation but encountered difficulties with the resulting expression $$\int \frac{1 + b \frac{x^{m - n}}{(-x + 1)^m}}{x(1 - b \frac{x^{m - n}}{(-x + 1)^m})} \, dx$$. The community is asked to provide alternative methods or insights into the context of this integral.

PREREQUISITES
  • Understanding of indefinite integrals and integration techniques
  • Familiarity with algebraic manipulation in calculus
  • Knowledge of logarithmic functions and their properties
  • Experience with substitution methods in integration
NEXT STEPS
  • Research advanced integration techniques, such as partial fraction decomposition
  • Explore the method of residues for complex integrals
  • Study the application of integration by parts in complex integrals
  • Investigate the context of integrals in mathematical physics or engineering problems
USEFUL FOR

Mathematicians, calculus students, and anyone involved in advanced integration techniques or seeking to understand complex integral forms.

Elina_Gilbert
Messages
1
Reaction score
0
I have the following integration -

$$\int \frac{2}{x - b \frac{x^{m - n + 1}}{(-x + 1)^m}} \, dx $$

To solve this I did the following -
$$\int \frac{1 - b \frac{x^{m - n}}{(-x + 1)^m}+1 + b \frac{x^{m - n}}{(-x + 1)^m}}{x(1 - b \frac{x^{m - n}}{(-x + 1)^m})} \, dx $$

Which gives me -

$$log(x) + C+ \int \frac{1 + b \frac{x^{m - n}}{(-x + 1)^m}}{x(1 - b \frac{x^{m - n}}{(-x + 1)^m})} \, dx $$

No matter what substitution I do, I couldn't solve the integral -

$$\int \frac{1 + b \frac{x^{m - n}}{(-x + 1)^m}}{x(1 - b \frac{x^{m - n}}{(-x + 1)^m})} \, dx $$

Can anyone please suggest what I did wrong? Please suggest me another method to solve this?
 
Physics news on Phys.org
May I ask what context this integral comes from?
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K