Indefinite Integral: $\int \frac{1}{\sqrt{\sin 2x}}dx$

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juantheron
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$\displaystyle \int \frac{1}{\sqrt{\sin 2x}}dx$
 
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jacks said:
$\displaystyle \int \frac{1}{\sqrt{\sin 2x}}dx$

How are you expecting this to be expressed? It is not elementary, but is an elliptic integral of the first kind.

CB
 
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