Indeterminate Forms: Converging to e & 1

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SUMMARY

The discussion centers on the concept of indeterminate forms in calculus, specifically examining the limit \(\lim_{n \rightarrow \infty} (1 + 1/n)^n\), which converges to the mathematical constant e. The user initially confuses this with the sequence \(a_n = 1^n\), which converges to 1 as it is a constant function. The clarification confirms that the limit of the original sequence is indeed e, while the limit of the constant sequence is 1.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with indeterminate forms
  • Knowledge of the mathematical constant e
  • Basic proficiency in LaTeX for mathematical notation
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  • Study the properties of indeterminate forms in calculus
  • Explore the derivation of the limit \(\lim_{n \rightarrow \infty} (1 + 1/n)^n\)
  • Learn about sequences and their convergence criteria
  • Investigate the applications of the constant e in various mathematical contexts
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Students and educators in mathematics, particularly those focusing on calculus and limits, as well as anyone interested in the properties of exponential functions and their convergence.

JG89
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I know [tex]\lim_{n \rightarrow \infty} (1 + 1/n)^n = \lim_{n \rightarrow \infty} 1^{\infty}[/tex], which is an indeterminate form, converging to e in this case. But what if the original sequence is [tex]a_n = 1^n[/tex]. Then as n tends to infinity, the function converges to 1 (because it's constant and the limit of a constant function is any term of the sequence). Is my reasoning correct here?EDIT: The original sequence is (1 + 1/n)^n, I messed up my latex.
 
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Yes, you are correct.
 

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