- #1

Alex_F

- 7

- 1

Considering the below equality (or equivalency), could someone please explain how the bounds and indices are shifted?

$$\sum_{i=2}^{k}(h_i/f_{i-1})=\int_{1}^{k}(h(i)/f(i))di$$

$$\sum_{i=2}^{k}(h_i/f_{i-1})=\int_{1}^{k}(h(i)/f(i))di$$

Last edited: