Induced Current Direction in a Changing Magnetic Field

AI Thread Summary
The discussion centers on the direction of induced current in a loop subjected to a changing magnetic field. An increasing magnetic flux through the loop necessitates a clockwise induced current to oppose the change, generating a downward magnetic field. However, confusion arises regarding whether the overall magnetic field entering and exiting the loop negates the need for induced current. The participants debate if the change in flux alone mandates induced current, despite the field's natural flow. Ultimately, the consensus leans towards the necessity of induced current due to the increasing flux.
guyvsdcsniper
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Homework Statement
What will be the direction of the induced current for the second image?
Relevant Equations
Lenz's Law
So for the first question it is very straight forward. The magnetic field is going through the loop, increasing the flux through the loop. The induced current must flow clockwise in order to generate a field that goes through the loop in a downward direction to oppose the change.The second question is stumping me. Maybe I am just over thinking it.
There is still a magnetic flux going through the the loop. The field flows from north to south. So the magnetic field enters the loop and exits it as well. So would that mean there is no induced current since over all the magnetic field enters and leaves the loop on its own. There wouldn't need to be an induced current to oppose the magnetic field?

Or does the fact that there is a change in flux mean there has to be an induced current, and since there is a magnetic field incoming and increasing toward the loop, the induced current must be clock wise to oppose the increase in flux.

Screen Shot 2021-11-14 at 1.08.55 PM.png
 
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quittingthecult said:
So would that mean there is no induced current since over all the magnetic field enters and leaves the loop on its own. There wouldn't need to be an induced current to oppose the magnetic field?
I think so too. When we see it from the backside N is our left S is right so we should expect the reverse current if any.
 
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