Inelastic car collision, answers aren't matching up

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Homework Help Overview

The discussion revolves around an inelastic collision problem involving two cars with specified masses and velocities. The original poster attempts to calculate the final velocity of one car after the collision but encounters discrepancies between their calculations and the answer key.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to consider the direction of the cars' velocities, questioning how this affects the calculations. There is mention of using an equation that accounts for the cars moving in opposite directions.

Discussion Status

Some participants have offered guidance on the importance of direction in the calculations. The original poster has made progress in their understanding by adjusting their approach to the problem, indicating a productive direction in the discussion.

Contextual Notes

There is a mention of the original poster's lack of recent physics knowledge, which may influence their understanding of the problem setup and equations involved.

BananasAreCool
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Homework Statement


Car A, having a mass of 1.30 x 10+3kg is traveling at 60.0 km/h due east when it collides with car B, having a mass of mass 1.70 x 10+3kg traveling at 40.0 km/h due west. If the collision is totally inelastic, find the final velocity of car B.
.

Homework Equations


I'm using the equation
m1v⃗ 1+m2v⃗ 2=(m1+m2)vf

The Attempt at a Solution


I'm getting 146,000 = (3000)Vf which I'm then dividing to get a velocity of 48.66. But the answer key is telling me 3.33km/h due east. I haven't taken physics in years and am super rusty so any help would be much appreciated.
 
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Hi BananasAreCool, Welcome to Physics Forums.

Did you take into account the fact that the cars are traveling in opposite directions?
 
gneill said:
Hi BananasAreCool, Welcome to Physics Forums.

Did you take into account the fact that the cars are traveling in opposite directions?

That's what I was thinking was the problem, what is the equation for them moving in opposite directions?
 
BananasAreCool said:
That's what I was thinking was the problem, what is the equation for them moving in opposite directions?
I was just able to figure it out, I had to subtract instead of add the two so instead of getting 146,000 I got 10,000, which divided by 3,000 equals to 3.33km/h.
 
BananasAreCool said:
I was just able to figure it out, I had to subtract instead of add the two so instead of getting 146,000 I got 10,000, which divided by 3,000 equals to 3.33km/h.
Yup. Well done.
 

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