1. The problem statement, all variables and given/known data A bullet is fired vertically into a 1.20 kg block of wood at rest directly above it. If the bullet has a mass of 24.0g and a speed of 540 m/s , how high will the block rise after the bullet becomes embedded in it? 2. Relevant equations 1/2mv^2+mgh=1/2mvf^2+mgh mv=mvf 3. The attempt at a solution I know that for this i must use momentum to find the final v which would be mV=(m+M)V' then i use that V' to find height 1/2mV'^2=(m+M)gh I solved this and I got an answer of 413 meters this is wrong. I do not know what im doing wrong.