Inelastic Collisions: Solving m1v1 + m2v2 = m1v1' + m2v2

[marshall4]

If i have the equation

m1v1 + m2v2 = m1v1' + m2v2'

would i have to use any calulus to find either velocity of the second object?

What is that the equation for? Is it inelastic collisions?

 

[pmb]

Originally posted by marshall4
If i have the equation

m1v1 + m2v2 = m1v1' + m2v2'

would i have to use any calulus to find either velocity of the second object?

What is that the equation for? Is it inelastic collisions?

You don't need calculus. Simple algebra. Just solve for v2.

This is the equation for conservation of momentum. It holds in both elastic and inelastic collisions. It's also valid in relativity if the m's are what some people call 'relativistic mass.' In such cases the m's are conserved. I.e. the sum of the m's before the collision is the sum of the m's after the collision.



Pete

 

[marshall4]

Originally posted by pmb
You don't need calculus. Simple algebra. Just solve for v2.

This is the equation for conservation of momentum. It holds in both elastic and inelastic collisions. It's also valid in relativity if the m's are what some people call 'relativistic mass.' In such cases the m's are conserved. I.e. the sum of the m's before the collision is the sum of the m's after the collision.



Pete

Doesn't the ' mean prime?

What is the ' there for?

What is the equation for completely inelastic collisions?

 

[pmb]

Originally posted by marshall4
Doesn't the ' mean prime?

What is the ' there for?

What is the equation for completely inelastic collisions?

Actually I meant to write a quote, i.e. "relativistic mass"

I want to applogize. I made an error in that last post. I made a web page on all of this a few weeks ago. See

www.geocities.com/physics_world/sr/inertial_mass.htm

The equation I posted above should have read

m₁v₁ + m₂v₂ = m₃v₃ + m₄v₄

This will hold in all collisions both eleastic and inelastic, and in both Newtonian mechanics and relativistic mechanics.

Particle N with mass m_N and velocity v_N. The mass may change in the collision.

Pete

 

[nautica]

The ' is only there to differeniate the original value from the final value.

Nautica