Inequality question -- Need help getting started...

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SUMMARY

This discussion focuses on understanding inequalities involving absolute values, specifically the expression |x-a|. Participants emphasize the importance of considering two cases based on the sign of (x-a): the first case being -(x - a) and the second case being (x - a). A critical property highlighted is that when multiplying both sides of an inequality by a positive number, the direction of the inequality remains unchanged, while multiplying by a negative number reverses the inequality. The conversation underscores the cumulative nature of mathematics, suggesting that reviewing foundational concepts is essential for grasping more advanced topics.

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Homework Statement
Please see below
Relevant Equations
Please see below
For this,
1679620253187.png

I am confused how to show that they are equivalent. Can some please give me some guidance?

Many thanks!
 
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What is always the first step when absolute values are involved? Two cases for |x-a|, depending on the sign of x-a.
Where can you go from there?
 
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FactChecker said:
What is always the first step when absolute values are involved? Two cases for |x-a|, depending on the sign of x-a.
Where can you go from there?
Thanks for your reply @FactChecker!

First case is

-(x - a)

Second case is

x - a
 
Right. Now you need to show some work using that.
 
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FactChecker said:
Right. Now you need to show some work using that.
Thanks @FactChecker!

##0 < -(x - a) < \delta##
##0 < x - a <\delta##

Many thanks!
 
Callumnc1 said:
Thanks @FactChecker!

##0 < -(x - a) < \delta##
##0 < x - a <\delta##

Many thanks!
Nevermind, I understand now. It seems so strange that you can multiply all three sides of an equality by the same number. I don't know what this property is called thought.
 
Callumnc1 said:
I am confused how to show that they are equivalent. Can some please give me some guidance?
For the continued inequality ##0 < |x - a| < \delta##, it's helpful to draw a sketch or two of the number line with a in an arbitrary position. x will then have to be somewhere inside a band of width ##2\delta## around a, but excluding a itself.
Callumnc1 said:
Nevermind, I understand now. It seems so strange that you can multiply all three sides of an equality by the same number. I don't know what this property is called thought.
The statement you started with is not an equation -- it's an inequality. There is a property of equations that you can multiply both sides of an equation by any nonzero number to get a new, equivalent equation. This idea can be extended to a continued equation.

There is a similar property for inequalities, but with a twist. You can multiply both sides of an inequality by a positive number to get a new, equivalent inequality. This also can be extended to continued inequalities. The twist is that if you multiply both sides by a negative number, the direction of the inequality must change.

Yet again, the very large gaps in your mathematical background are causing you to spend a lot of time merely trying to understand what would be immediately obvious to someone who didn't have these gaps.
 
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Mark44 said:
Yet again, the very large gaps in your mathematical background are causing you to spend a lot of time merely trying to understand what would be immediately obvious to someone who didn't have these gaps.
Amen! Mathematics is very cumulative. Anything that you were taught earlier will be used over and over in what follows. It can be very beneficial to review earlier material until it becomes natural to you.
 
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