Find the set of points that satisfy:|z|^2 + |z - 2*i|^2 =< 10

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Homework Help Overview

The problem involves finding the set of points that satisfy the inequality |z|^2 + |z - 2*i|^2 <= 10, which relates to complex numbers and geometric interpretations in the coordinate plane.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss expressing the complex number z in terms of its real and imaginary components, leading to an expansion of the inequality. There is a focus on transforming the inequality into a recognizable geometric form, such as that of a circle.

Discussion Status

Some participants have provided calculations and interpretations of the inequality, exploring the transformation into a circle's equation. There is acknowledgment of a mistake in the radius, and further clarification is sought regarding the correctness of the calculations.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the extent of direct assistance provided. The discussion reflects a mix of interpretations and attempts to clarify the problem setup.

Makadamij
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Homework Statement
Find and draw the set of all points that satisfy the following condition: |z|^2 + |z - 2*i|^2 =< 10, where z is a complex number.
Relevant Equations
|z| = sqrt(a^2 + b^2)
z = a + b*i
Hello everyone,

I've been struggling quite a bit with this problem, since I'm not sure how to approach it correctly. The inequality form reminds me of the equation of a circle (x^2 + y^2 = r^2), but I have no idea how to be sure about it. Would it help just to simplify the inequality in terms of solving the absolute value of z and z-2i ?

I would be very thankful for any advices and solutions.

Best wishes,

Makadamij
 
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What happens if you express ##z = x + iy## and expand the inequality?
 
Hello, thank you for participating in my problem. By expressing and expanding I get:

|x+yi|^2 + |x+(y-2)i|=< 10
x^2 + y^2 + x^2 + (y-2)^2 =< 10
2x^2 + 2y^2 - 4y + 4 =<10
2x^2 + 2y^2 - 4y =< 6 /:2
x^2 + y^2 - 2y =< 3

This can be transformed to the equation of a circle

x^2 + (y-1)^2 - 2 =< 3
x^2 + (y-1)^2 =< 5

So I get the formula of a cirlce with radius sqrt(5), which centre point is at S(0,1).
Are my calculations therefore correct or am I missing something?
 
Makadamij said:
Hello, thank you for participating in my problem. By expressing and expanding I get:

|x+yi|^2 + |x+(y-2)i|=< 10
x^2 + y^2 + x^2 + (y-2)^2 =< 10
2x^2 + 2y^2 - 4y + 4 =<10
2x^2 + 2y^2 - 4y =< 6 /:2
x^2 + y^2 - 2y =< 3

This can be transformed to the equation of a circle

x^2 + (y-1)^2 - 2 =< 3
x^2 + (y-1)^2 =< 5

So I get the formula of a cirlce with radius sqrt(5), which centre point is at S(0,1).
Are my calculations therefore correct or am I missing something?
You made a small mistake near the end.

You could check this yourself by setting ##w = z - i##. Now that you think it's a circle centred at ##0 + i##. You should get ##|w| \le R##.
 
I've spotted the mistake, thank you. The radius is supposed to be 2, not sqrt(5). And also a kind thank you for all the advices. Problem is now solved :)
 
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