MHB Inequality with absolute value

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The discussion focuses on expressing inequalities with absolute values. The initial inequality, x < -5 or 8 < x, can be rewritten as |x - 3/2| > 13/2, indicating that x is more than 13/2 units away from the midpoint of 3/2. A follow-up example involves the inequality 1 < x < 9, which translates to |x - 5| < 4, showing that x is within 4 units of the midpoint 5. Participants share insights on how to approach these transformations effectively. Understanding the relationship between the midpoint and distance is crucial for solving such inequalities.
karush
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Write as one inequality with an absolute value

x<-5 or 8<x

not sure how you introduce the absolute value in this to solve it.

thanks ahead
 
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Re: ineqaulity with absolute value

Hello, karush!

"Write as one inequality with an absolute value: .x < -5 .or .8 < x."
Code:
            : - - 13/2 - - : - - 13/2 - - :
      ======o--------------*--------------o======
           -5             3/2             8
Note that the midpoint of the interval is 3/2.

All the points satisfying the inequality are greater than 13/2 units from the midpoint.

Therefore: .|x - 3/2|. > . 13/2
 
Re: ineqaulity with absolute value

yes that's makes sense that the book answer also
 
Re: ineqaulity with absolute value


To follow up on this topic, consider this problem.

Write as one inequality with an absolute value: .$1\, <\,x\,<\,9$
Note that the midpoint of the interval is 5.

Code:
          : - - 4 - - : - - 4 - - :
      ----o===========*===========o----
          1           5           9

We see that the values of $x$ are all within 4 units of 5.

Therefore: .$|x - 5| \:<\:4$
 
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