Inferring Shape of Phasors in Multi-Slit Diffraction

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SUMMARY

The discussion focuses on inferring the shape of phasors in multi-slit diffraction, emphasizing the difference between single-slit and multiple-slit analyses. For multiple slits, phasors associated with each slit must be aligned to produce maxima, while closed polygons formed by phasors indicate minima. The phase angle between adjacent sources is given by the formula ## \phi=(\frac{2 \pi}{\lambda}) d \sin{\theta} ##, which is crucial for understanding phasor alignment. The importance of comparing single-slit and double-slit simulations is highlighted as a key method for visualizing these concepts.

PREREQUISITES
  • Understanding of phasors in wave physics
  • Familiarity with the principles of diffraction
  • Knowledge of the formula for constructive interference, ## m \lambda=d \sin{\theta} ##
  • Basic vector addition concepts
NEXT STEPS
  • Explore the implications of the phase angle formula ## \phi=(\frac{2 \pi}{\lambda}) d \sin{\theta} ## in multi-slit diffraction
  • Analyze single-slit versus double-slit diffraction simulations
  • Investigate the role of phasor alignment in producing intensity maxima
  • Review vector addition techniques in the context of wave interference
USEFUL FOR

Physics students, educators, and researchers interested in wave optics, particularly those studying diffraction patterns and phasor analysis.

hidemi
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Homework Statement
At a bright diffraction line phasors associated with waves from the slits of a multiple-slit barrier:
A. are aligned
B. form a closed polygon
C. form a polygon with several sides missing
D. are parallel but adjacent phasors point in opposite directions
E. form the arc of a circle

The correct answer is A
Relevant Equations
d * sin(theta) = m * lambda
I know that phasors of a single-slit diffraction form a closed polygon or circle, but how could we infer the shape when phasors generated by slits of a multiple-slit barrier?
 
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The ## m \lambda=d \sin{\theta} ## for constructive interference is sort of on the right track, but what you are needing is the phase angle between phasors from adjacent sources a distance ## d ## apart: ## \phi=(\frac{2 \pi}{\lambda}) d \sin{\theta} ##. Using the first expression, (since you are told that the sources constructively interfere), what can you say about ## \phi ##? Will the phasors be aligned?
 
hidemi said:
I know that phasors of a single-slit diffraction form a closed polygon or circle ...
Closed polygon's give minima (zero intensity), not maxima.

Think of adding phasors in the same way as adding vectors. The resultant is zero only when the vectors form a closed polygon.

There is an important difference between a single-slit and multiple-slits when using phasors.

For a single-slit analyis, each point in the aperture has a phasor. The phasors are aligned in only one situation - for the central direction.

For a multiple-slit analysis we associate each slit with a single phasor. A maximum is produced whenever the phasors are aligned (unlike a single-slit).

This video gives quite a good insight. You need to compare the single-slit and double-slit simulations carefully.
 
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Steve4Physics said:
Closed polygon's give minima (zero intensity), not maxima.

Think of adding phasors in the same way as adding vectors. The resultant is zero only when the vectors form a closed polygon.

There is an important difference between a single-slit and multiple-slits when using phasors.

For a single-slit analyis, each point in the aperture has a phasor. The phasors are aligned in only one situation - for the central direction.

For a multiple-slit analysis we associate each slit with a single phasor. A maximum is produced whenever the phasors are aligned (unlike a single-slit).

This video gives quite a good insight. You need to compare the single-slit and double-slit simulations carefully.

Thank you! I got it
 
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Likes Steve4Physics and Charles Link
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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