Infinite geometric series problem

Click For Summary
SUMMARY

The discussion centers on the evaluation of the infinite geometric series represented by the formula \(\sum_{n=1}^\infty \frac{(-3)^{n-1}}{4^n}\). Participants clarify the transition from the original series to the expression \(\frac{1}{4}\sum_{n=1}^\infty \left(-\frac{3}{4}\right)^{n-1}\). The factor of \(\frac{1}{4}\) is factored out due to the common denominator, while the exponent adjustment occurs as part of the geometric series formula. The conversation emphasizes the importance of understanding the manipulation of series terms in calculus.

PREREQUISITES
  • Understanding of infinite series and convergence
  • Familiarity with geometric series formulas
  • Basic algebraic manipulation skills
  • Knowledge of summation notation
NEXT STEPS
  • Study the properties of geometric series and their convergence criteria
  • Learn how to manipulate summation notation in calculus
  • Explore examples of infinite series with varying ratios
  • Investigate the application of series in real-world problems
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in mastering infinite series and their applications.

MillerGenuine
Messages
64
Reaction score
0

Homework Statement



[tex]\sum_{n=1}^\infty \frac{(-3)^{n-1}}{4^n}[/tex]



The Attempt at a Solution



[tex]\sum_{n=1}^\infty \frac{(-3)^n-1}{4^n}[/tex]


[tex]\frac{1}{4}\sum_{n=1}^\infty \frac(-{3}{4})^{n-1}[/tex]


Can some one please explain how they got from the first step to the 2nd. How do you pull out a 1/4 and how does the "n" on the 4 dissapear?
Thanks
 
Physics news on Phys.org
Can you fix your third summation? It's all fouled up.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K