Infinite Potential Colliding with Wave Function: Is it Correct?

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SUMMARY

The discussion centers on the wave function behavior of a particle colliding with a defined potential. For region (I), where the potential is infinite (V = ∞, x < 0), the wave function is confirmed to be zero. In region (II), where the potential is negative (V = -V0, 0 < x < a), the wave function takes the form A sin(kx), where k is a constant derived from the Schrödinger equation. This confirms the expected behavior of quantum particles in potential wells.

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Potential and wave function

If a particle comes from +infinite and collides with a potential of the form :

V = ∞ , x < 0 (I)
-V0 , 0<x<a (II)
0 , x≥a (III)

Is the wave function for region (I) = 0? And for region (II) = A sin(kx) with k constant?

Really need to know if I'm correct, thanks
 
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rmfw said:
If a particle comes from +infinite and collides with a potential of the form :

V = ∞ , x < 0 (I)
-V0 , 0<x<a (II)
0 , x≥a (III)

Is the wave function for region (I) = 0? And for region (II) = A sin(kx) with k constant?

Really need to know if I'm correct, thanks

Yes region (I) has a 0 wave function. Region (II) requires a solution to the Schr. equation, but it should be similar to that.
 

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