Infinite series with all negative terms

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The discussion centers on the convergence of infinite series with negative terms, specifically addressing the power series ∑(-1)n-1(xn/n). It highlights a paradox where traditional convergence tests typically require positive terms, yet the series converges for -1<x≤1, even when evaluating at -0.45 yields all negative terms. The conclusion drawn is that a series can indeed converge despite having all negative terms, as demonstrated by the example of -e. This challenges conventional understanding and emphasizes the need to consider specific series behavior in convergence tests. Overall, negative terms do not preclude convergence in infinite series.
Ibraheem
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Hello,

I have been reviewing my textbook lately, and I came across a rather paradoxical statements. all of the convergence tests in my book state that the terms of the series has to be positive. However, when I solved this power series ∑(-1)n-1(xn/n), I found that it converges for -1<x≤1, but when I plugged -0.45 to test if the infinite series will converge, I got all the terms negative. So my question is can a series converge if all its terms are negative?
 
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Yes. E.g. ##-e##.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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