Infinite Well with Sinusoidal Potential

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SUMMARY

The discussion centers on constructing the ground state wavefunction for a particle in a sinusoidal potential defined as V(x) = V_{0}sin(πx/L) within the range 0 < x < L. The solution for the infinite square well is given by φ_n = √(2/L)sin(nπx/L). Participants emphasize the need to apply the Schrödinger equation to the linear combination of energy eigenstates and suggest using trigonometric identities to simplify the potential terms, which will lead to recursive relations among the coefficients a_j. To find the ground state energy, minimization techniques may be required.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the Schrödinger equation.
  • Familiarity with the infinite square well model and its wavefunctions.
  • Knowledge of linear combinations of quantum states and their coefficients.
  • Basic proficiency in trigonometric identities and their applications in physics.
NEXT STEPS
  • Explore the application of the Schrödinger equation in non-constant potential scenarios.
  • Study the method of linear combinations of energy eigenstates in quantum mechanics.
  • Learn about minimization techniques for determining ground state energies in quantum systems.
  • Investigate the use of trigonometric identities in simplifying quantum mechanical potentials.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on potential wells and wavefunction construction, as well as educators seeking to enhance their understanding of sinusoidal potentials in quantum systems.

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Homework Statement



Assume a potential of the form [tex]V(x)=V_{0}sin({\frac{\pi x}{L}})[/tex] with 0<x<L and [tex]V(x)=\infty[/tex] outside this range. Assume [tex]\psi = \sum a_{j} \phi_{j}(x)[/tex], where [tex]\phi_{j}(x)[/tex] are solutions for the infinite square well. Construct the ground state wavefunction using at least 10 basis functions.


Homework Equations



I obtained the solution [tex]\phi_{n} = \sqrt{\frac{2}{L}} \sin({\frac{n\pi x}{L}})[/tex] for the infinite square well with zero potential inside.

The Attempt at a Solution



After obtaining the solution shown above, I attempted to expand the summation. I know that I want to do a linear combination of energy eigenstates, however, I am not sure what to do about the leading coefficients. I have found by searching that [tex]a_{j} = \int_{-\infty}^{\infty} \phi_{j}^{*}(x) \psi dx[/tex], but how can I solve this if I'm using the [tex]a_{j}[/tex]'s to find [tex]\psi[/tex]?

Any help or advice would be greatly appreciated. Thanks!
 
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You need to apply the Schrödinger equation to your linear combination, since the particle in a box basis are not solutions once we turn on this sinusoidal potential. You'll probably be able to use a trig identity to simplify the potential terms with [itex]V(x) \phi_k(x)[/itex], then group like orders of [itex]\sin(n\pi x/L)[/itex]. This will give you some recursive relations among the [itex]a_j[/itex]. To obtain the ground state energy, you might have to minimize something.
 

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