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Infinity over infinity squared

  1. Nov 3, 2013 #1

    Qube

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    1. The problem statement, all variables and given/known data

    http://i.minus.com/jbwNvxhmIxeKxB.png [Broken]


    3. The attempt at a solution

    I'm unclear on whether the entire log is being squared or if just the (1-x) term in the denominator is being squared. I know if it's the latter, then the exponent can be moved to in front of the log.
     
    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Nov 3, 2013 #2

    Dick

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    I would say it's almost certainly the (1-x) that is squared.
     
    Last edited by a moderator: May 6, 2017
  4. Nov 3, 2013 #3

    arildno

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    Hi, there!
    My interpretation is that it is only the argument of the log function that is squared.
    Why?

    Because if you wish to square the log, by far the most common conventions are either:
    a) [itex]\ln^{2}(1-x)[/itex]
    b) [itex](\ln(1-x))^{2}[/itex]
     
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