Maximizing Range of 0 < x < 1: Comparing Expressions x-1 and x-1/2

  • Thread starter Thread starter Schnellmann
  • Start date Start date
  • Tags Tags
    Range
Click For Summary
SUMMARY

The discussion centers on comparing the expressions \(1/x\) and \(1/\sqrt{x}\) for the range \(0 < x < 1\). The correct interpretation reveals that \(1/x\) yields larger values than \(1/\sqrt{x}\) within this interval. The confusion arises from the misinterpretation of square roots, where the square root function only returns the principal (positive) root, thus limiting the range to \(1 < \text{range} < \infty\) for \(1/x\) and \(1 < \text{range} < \infty\) for \(1/\sqrt{x}\). The discussion clarifies that negative roots are not applicable in this context.

PREREQUISITES
  • Understanding of basic algebraic expressions
  • Familiarity with the concept of limits and ranges in mathematics
  • Knowledge of square roots and their properties
  • Ability to interpret mathematical notation and expressions
NEXT STEPS
  • Study the properties of rational functions, specifically \(1/x\) and \(1/\sqrt{x}\)
  • Learn about the implications of principal square roots in mathematical expressions
  • Explore the concept of limits and how they apply to functions approaching infinity
  • Review mathematical comparisons of functions over specified intervals
USEFUL FOR

Students in mathematics, educators teaching algebra, and anyone interested in understanding function comparisons and their behaviors within specific ranges.

Schnellmann
Messages
21
Reaction score
6

Homework Statement



I was doing some multiple choice questions. One question was:

"Which of the expressions below has the largest value for 0 < x < 1

The two relevant options (dismissing those obviously wrong) were:

x-1 (can't do superscript on my iPhone - that should read X to the power of -1 ie 1/x)

Other option was x-1/2 meaning one over the square root of x

I took the question to mean which equation gives the greatest range for values of x between zero and one.

The answer was given as 1/x but that confuses me because a) both have the range from 1 < range < infinity It is true that for any individual x then 1/x is larger than one over the square root of x but I thought that you couldn't compare infinities in that way.

Also I thought that if you take the square root of x then doesn't it have a positive and negative root such that you actually have a range of - infinity < range < -1 as well as the range 1 < range < infinity.

Where am I going wrong?

Homework Equations

The Attempt at a Solution

 
Physics news on Phys.org
Schnellmann said:

Homework Statement



I was doing some multiple choice questions. One question was:

"Which of the expressions below has the largest value for 0 < x < 1

The two relevant options (dismissing those obviously wrong) were:

x-1 (can't do superscript on my iPhone - that should read X to the power of -1 ie 1/x)

Other option was x-1/2 meaning one over the square root of x

I took the question to mean which equation gives the greatest range for values of x between zero and one.

The answer was given as 1/x but that confuses me because a) both have the range from 1 < range < infinity It is true that for any individual x then 1/x is larger than one over the square root of x but I thought that you couldn't compare infinities in that way.

Also I thought that if you take the square root of x then doesn't it have a positive and negative root such that you actually have a range of - infinity < range < -1 as well as the range 1 < range < infinity.

Where am I going wrong?

You may have misinterpreted the question. What about this:

For a given ##x## between ##0## and ##1##, which of the following expressions gives the largest value?

On a second point about square roots. The square root of ##1## is ##1##. As in, ##\sqrt{1} = 1^{1/2} = 1## In other words, the square root has a unique, positive value.

There is another "root", which is: ##y = -\sqrt{x}## which also has the property that ##y^2 = x##. But this ##y## is not the square root.
 
  • Like
Likes   Reactions: TomHart

Similar threads

Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 47 ·
2
Replies
47
Views
5K
Replies
4
Views
4K
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K