Initial Velocity (Without time and acceleration)

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Homework Statement


You are standing at the top of a cliff that has a stair step configuration. There is a vertical drop of 7 m at your feet, then a horizontal shelf of 9 m, then another drop of 3 m to the bottom of the canyon, which has a horizontal floor. You kick a 0.26 kg rock, giving it an initial horizontal velocity that barely clears the shelf below.

What initial horizontal velocity v will be required to barely clear the edge of the shelf
below you? How far from the bottom of the second cliff with the rock land?

Homework Equations



d=Vi(t)+(1/2)(a)(t^2)

The Attempt at a Solution


Cant seem to get around the problem without knowing more.
 
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kuruman said:
Can you find the time required for the rock to reach the point where it barely clears the edge of the shelf?

I haven't been able to
 
You can find the time by using gravity and the fact that the first step is 7 meters down. How long does it take for the rock to fall 7 m? If you find it you can calculate how fast it must travel in a horizontal direction.
 
Anden said:
You can find the time by using gravity and the fact that the first step is 7 meters down. How long does it take for the rock to fall 7 m? If you find it you can calculate how fast it must travel in a horizontal direction.

Could you help me out a little more?
 
Anden said:
You can find the time by using gravity and the fact that the first step is 7 meters down. How long does it take for the rock to fall 7 m? If you find it you can calculate how fast it must travel in a horizontal direction.

So I am assuming you mean:
7m/9.8=.7142857s to make it to the bottom =t

using

d=(Vi+Vf/2)(t)
therefore
9m=(0+Vf/2)(.7142857s)
Vf=25.2

that not right?