Instances where Logarithmic Differentiation doesn't work?

Click For Summary
Logarithmic differentiation is generally effective for finding derivatives of complex functions, but it may not always be the simplest method for simpler equations. While it works well for complicated expressions, such as y = (3x^2 + 5)^(1/x) or y = (sin x)^(x^3), it can be more cumbersome than direct differentiation for straightforward cases like y = x^2. The discussion highlights that while logarithmic differentiation is a valuable tool, its necessity depends on the complexity of the function being differentiated. Overall, it is important to assess whether the added complexity of logarithmic differentiation is justified based on the specific equation. Understanding when to apply this technique can enhance efficiency in calculus.
in the rye
Messages
83
Reaction score
6
Hey,

In my class we just learned about logarithmic differentiation. I can see this being useful when taking the derivative of a complex function since it could be messy. But, I tried it on simpler equations as well. Everything I tried it on it seemed to work. Are there ever instances that it does not work?

To make sure we are using the same definition of logarithmic differentiation, I simply mean taking the log of both sides of an equation before taking its derivative. So where:

y = x2
ln y = ln (x2)
1 / y * y' = 1 / x2 * 2x
y' = 2y / x
y' = 2x

Certainly just taking the derivative of this is easier, but it's just an example.
 
Physics news on Phys.org
in the rye said:
Hey,

In my class we just learned about logarithmic differentiation. I can see this being useful when taking the derivative of a complex function since it could be messy. But, I tried it on simpler equations as well. Everything I tried it on it seemed to work. Are there ever instances that it does not work?
To the best of my knowledge, no.
in the rye said:
To make sure we are using the same definition of logarithmic differentiation, I simply mean taking the log of both sides of an equation before taking its derivative. So where:

y = x2
ln y = ln (x2)
1 / y * y' = 1 / x2 * 2x
y' = 2y / x
y' = 2x

Certainly just taking the derivative of this is easier, but it's just an example.
Your example is a very simple one, for which log differentiation is a lot more work than it would be by simpler means.

Here are some examples where log differentiation would be very useful.
1. ##y = (3x^2 + 5)^{1/x}##
2. ##y = (\sin x)^{x^3}##
(from https://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/logdiffdirectory/LogDiff.html)
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K