# B Instantaneous speed without using calculus

1. Mar 4, 2017

### rajeshmarndi

Say a particle cover y=t^2 distance.

at t=1s total distance cover = 1m
at t=2s total distance cover = 4m
at t=3s total distance cover = 9m
at t=4s total distance cover = 16m

So the instantaneous speed at t=2s is 9 - 4 = 5m i.e 5m/s.

To get the instantaneous speed at t=2s and t=3s, I take the instantaneous speed 5m/s at t=2s, as the average instantaneous speed between t=2s and t=3s as 5.

So the instantaneous speed at t=2s and t=3s become 4m and 6m. Also the instantaneous speed

at t=2.1s become 4.1
at t=2.3s become 4.3 and so on.

Here we get the instantaneous speed without using Δt→0. But I know to calculate instantaneous speed, calculus was invented.

Thanks.

[edit :]

at t=2.1s become 4.2
at t=2.3s become 4.6 and so on.

Last edited: Mar 4, 2017
2. Mar 4, 2017

### phinds

wrong, it's 4.2
wrong, it's 4.6

And you get it incorrectly.

Was there as question in all of this or did you just want to demonstrate incorrect extrapolation?

3. Mar 4, 2017

### rajeshmarndi

correction .....
at t=2.1s become 4.2
at t=2.3s become 4.6 and so on.