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## Homework Statement

The position of an object as a function of time is given by x = At^2 + Bt + C

A = 8 m/s^2

B = 6 m/s

C = 4 m

## Homework Equations

v = u + at

a = v/t

## The Attempt at a Solution

I don't even know how to set this up!

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- Thread starter jensson
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- #1

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The position of an object as a function of time is given by x = At^2 + Bt + C

A = 8 m/s^2

B = 6 m/s

C = 4 m

v = u + at

a = v/t

I don't even know how to set this up!

- #2

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how does velocity relate to position?

how does acceleration relate to velocity?

how does acceleration relate to velocity?

- #3

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this question was on a quiz and I got it wrong.. I can't seem to make it make sense in my head. I have the answers and I still can't figure out how to get there.

- #4

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- #5

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V = dx/dt

but the position is given has a quadratic equation.

V = 8t + 6t + 4/t

but that doesn't seem right

- #6

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[tex]x = At^2 + Bt + C[/tex]

[tex]v = 2At^1 + Bt^0 + 0[/tex] You always decrease the power of the variable by one--but if there is no variable, then the derivate is zero---in other words: if there is no variable, it is constant, and thus the slope/change is zero.

Then the 'B' term becomes just B, and the C term drops out (is zero). ====>

[tex]v = 2At + B[/tex]

then you repeat to find the acceleration, and plug in to find the values.

Does that make sense? Make sure you review your derivatives :)

What does the acceleration equal?

- #7

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- #8

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They key is just not getting overwhelmed by it; go one step at a time, one problem at a time, one concept at a time.

Does the derivative I did above make sense?

- #9

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A 2 problem quiz every thursday and thanks to this problem here I got 1/2 wrong :(

I can see the pattern in your steps, but I have not studied derivatives yet so I don't know why it was done

- #10

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Let me know if something in particular doesn't make sense, I'll try to help.

Don't worry. You'll be fine.

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