Instantaneous Velocity graph problem

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To find the instantaneous velocity at 1 second, one must determine the slope of the position versus time graph at that point. The coordinate provided is (1,4), indicating the position at 1 second, but additional information about the motion is necessary to calculate the velocity accurately. Differentiating the position function or drawing a tangent line at the point can yield the instantaneous velocity. Without a complete function or more data points, estimating the velocity remains challenging. Therefore, knowing the full context of the motion is essential for an accurate calculation.
iiskenny
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Find the instantaneous velocity at 1 s.
Answer in units of m/s.

the coordinate for 1s is (1,4)

How do i find the instantaneous velocity?
 
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welcome to pf!

hi iiskenny! welcome to pf! :smile:
iiskenny said:
Find the instantaneous velocity at 1 s.
Answer in units of m/s.

the coordinate for 1s is (1,4)

How do i find the instantaneous velocity?

by differentiating, or by drawing a tangent to the graph …

but what's the rest of this function? :confused:
 
Velocity is defined as the rate of change of position divided by the rate of change of time.

This is the same as saying that velocity is the slope of the position vs. time graph.

Therefore, instantaneous velocity at 1s is the slope of the position vs. time graph at t=1s.
 
But, as both tiny-tim and Beaker87 have said, just knowing the position is not enough! That's like saying "at 2:00, a car was at 4th st and Central ave. How fast was it going?"!

You need to know something about it motion through that point. An actual "position function", telling where it was at different times, would be excellent- take the derivative of the function. If you are given a "x versus t" graph, you can estimate the slope of the tangent line at the given point. If you are given a position at another time, before or after this t= 1 you can estimate the speed at t= 1. If you are given the position at times before and after as well as at t= 1, you can get a better estimate.

Now, what information are you really given? What is the full statement of the question?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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