Integral between -infinity and +infinity

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The integral of the function e^-iwt / (a - iw) from -infinity to +infinity requires the use of substitution to simplify the expression. The correct substitution is u = a - iw, leading to du/dw = -i and dw = du / -i. The integral can be expressed as J = i e^{-at} ∫ (e^{ut}/u) du, which is classified as "non-elementary" due to its relation to the exponential integral function. This integral cannot be expressed in terms of elementary functions.

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integral between -infinity and +infinity of

e^-iwt / (a - iw) dw



u = a - iw

du/dw = -i

dw = du / -i

e^-iwt = e^(u+a)t / -iu du


its a homework question, so just a pointer as to which method to use would be appreciated, it says substitution, but I've tried the above and doesn't get me anywhere, maybe I am not choosing the correct substitution?

thanks for any help
 
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Have you been instructed to use substitution?
Have you tried ratonalizing the denominator?
 
rwooduk said:
integral between -infinity and +infinity of

e^-iwt / (a - iw) dw



u = a - iw

du/dw = -i

dw = du / -i

e^-iwt = e^(u+a)t / -iu du


its a homework question, so just a pointer as to which method to use would be appreciated, it says substitution, but I've tried the above and doesn't get me anywhere, maybe I am not choosing the correct substitution?

thanks for any help

Your exp(at) part has the wrong sign in the exponent. You should find that your integral, J, is
[tex]J \equiv \int \frac{e^{-iwt}}{a-iw} \, dw = i e^{-at} \int \frac{e^{ut}}{u} \, du[/tex]
This last form reveals that the integral is "non-elementary", because ##\exp(tu)/u## cannot be integrated found as a finite expression involving elementary functions; it involves the so-called exponential integral; see http://en.wikipedia.org/wiki/Exponential_integral .
 

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