Integral for a differential equation problem

1. Apr 10, 2008

sihag

i'm stuck on this relatively simply integral for a differential equation problem ...

| du / cos(pi/4 - u )
where | denotes the integral sign

some help ?

2. Apr 10, 2008

tiny-tim

Hi sihag!

Hint: substitute v = u - π/4.

(and copy the symbols below for future use! )

3. Apr 10, 2008

Gib Z

After letting $\frac{\pi}{4} - u =x$, all you need to know is $$\int \frac{1}{\cos x} dx = \log_e | \frac{1+\sin x}{\cos x} | + C$$.