Integral for a differential equation problem

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SUMMARY

The integral discussed is ∫ du / cos(π/4 - u). To solve this, a substitution of v = u - π/4 is recommended. After this substitution, the integral simplifies to ∫ 1/cos(x) dx, which can be evaluated using the formula ∫ 1/cos(x) dx = log_e |(1 + sin(x))/cos(x)| + C. This method effectively transforms the original problem into a more manageable form.

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  • Understanding of basic integral calculus
  • Familiarity with trigonometric identities
  • Knowledge of substitution methods in integration
  • Ability to manipulate logarithmic expressions
NEXT STEPS
  • Study integration techniques involving trigonometric functions
  • Learn about substitution methods in calculus
  • Explore the properties of logarithmic functions
  • Practice solving differential equations using integrals
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Students and professionals in mathematics, particularly those focusing on calculus and differential equations, will benefit from this discussion.

sihag
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i'm stuck on this relatively simply integral for a differential equation problem ...

| du / cos(pi/4 - u )
where | denotes the integral sign

some help ?
 
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sihag said:
∫ du / cos(π/4 - u)

Hi sihag! :smile:

Hint: substitute v = u - π/4. :smile:

(and copy the symbols below for future use! :smile:)
 
After letting \frac{\pi}{4} - u =x, all you need to know is \int \frac{1}{\cos x} dx = \log_e | \frac{1+\sin x}{\cos x} | + C.
 

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