Integral from 0 to 5 24e^-6t cos(2t) dt

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The discussion centers on evaluating the integral from 0 to 5 of the function 24e-6t cos(2t) dt. The user has identified the integration formula from an integral table, specifically (eax/(a2 + b2))(a cos bx + b sin bx). The main challenge lies in applying integration by parts to complete the evaluation. Participants emphasize the importance of evaluating the anti-derivative at the specified endpoints to finalize the solution.

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I need help with this integral.

w= the integral from 0 to 5

24e^-6t cos(2t) dt.

i found the the integration in the integral table.

(e^ax/a^2 + b^2) (a cos bx + b sin bx)

im having trouble finishing the problem from here.
 
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use integration by parts.
 


smith5753 said:
I need help with this integral.

w= the integral from 0 to 5

24e^-6t cos(2t) dt.

i found the the integration in the integral table.

(e^ax/a^2 + b^2) (a cos bx + b sin bx)

im having trouble finishing the problem from here.
What exactly are you having problems with? You have the anti-derivative, all you need to do now is evaluate it at then end points.
 

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