- #1

- 2

- 0

w= the integral from 0 to 5

24e^-6t cos(2t) dt.

i found the the integration in the integral table.

(e^ax/a^2 + b^2) (a cos bx + b sin bx)

im having trouble finishing the problem from here.

- Thread starter smith5753
- Start date

- #1

- 2

- 0

w= the integral from 0 to 5

24e^-6t cos(2t) dt.

i found the the integration in the integral table.

(e^ax/a^2 + b^2) (a cos bx + b sin bx)

im having trouble finishing the problem from here.

- #2

- 164

- 0

use integration by parts.

- #3

Hootenanny

Staff Emeritus

Science Advisor

Gold Member

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- 6

What exactly are you having problems with? You have the anti-derivative, all you need to do now is evaluate it at then end points.

w= the integral from 0 to 5

24e^-6t cos(2t) dt.

i found the the integration in the integral table.

(e^ax/a^2 + b^2) (a cos bx + b sin bx)

im having trouble finishing the problem from here.

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