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$\displaystyle (1)\;\; \int_{-\infty}^{\infty}\frac{x^2}{1+4x+3x^2-4x^3-2x^4+2x^5+x^6}dx$
The integral from negative infinity to infinity of the function $\frac{x^2}{1+4x+3x^2-4x^3-2x^4+2x^5+x^6}$ evaluates to $\pi$. This result is derived using techniques from complex analysis, specifically residue theory, which allows for the evaluation of improper integrals. The discussion highlights the significance of understanding the behavior of the polynomial in the denominator to determine the poles and their contributions to the integral.
PREREQUISITESMathematicians, students of advanced calculus, and anyone interested in complex analysis and integral evaluation techniques.