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Integral of a position v time graph; meaningless?

  1. Apr 10, 2007 #1
    So, you have a graph of velocity vs. time. You integrate, you get position. What if you have a position vs time graph? For example, meters vs. seconds. If you integrate it, you will get meters seconds. Now, does this mean anything? For example, ive heard of "watt hours" but i simply dont understand how this makes any sense. What would it mean to integrate a position vs time graph?
  2. jcsd
  3. Apr 10, 2007 #2
    One reason you might want to integrate it is to find the average position.

    <x>=1/T Int[x(t)dt]
  4. Apr 10, 2007 #3
    Watt hours (more commonly seen as kilowatt hours--kwh) are a unit of energy.

    Try multiplying the units for watts by the units for hours and see what you arrive with.

    (J/t) * t = Joules
  5. Apr 11, 2007 #4
    why not just call them joules then?
    ive seen products, such as surge protectors labeled with, "handles up to 16,000 joules."
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