MHB Integral with sinx in the denominator

[tmt1]

I have this integral

$$\int_{}^{} \frac{x}{sinx} dx$$

How can I approach solving this? I tried u-substitution with $u = sinx$. And I get

$$\int_{}^{} \frac{x}{cosx u} du$$, so I don't think that is an option. I'm also unsure of how I would apply integration by parts. Or can I simplify the expression in some way to make this easier?

 

[MarkFL]

That particular integrand does not have an anti-derivative expressible in elementary terms. :)

 

[alyafey22]

Regardless of the function not having an elementary anti-derivative, your substitution is wrong.