First part of the question was to work out the integral [tex]1/(y+cos(x))[/tex] between x=0 and x=pi/2 by using the substitution [tex]t=tan(x/2).[/tex](adsbygoogle = window.adsbygoogle || []).push({});

Got this to be [tex]\frac{2}{\sqrt{y^2-1}}arctan(\sqrt{\frac{y-1}{y+1}})[/tex]

The next question says HENCE find integral with the same limits of [tex]\frac{1}{(y+cos(x))^2}[/tex]

Ive tried using by parts to maybe get something minus the first integral but i can't get it to work. This exam is known for being full of horrible questions so anything is possible here

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# I Integrate 1/(y+cos(x))^2 dx

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