Integrate √(x2(x+3)) from -3 to 0.
2. The attempt at a solution
Here is what I did:
Let u=x+3, du=dx, x=u-3
Insert the bounds and change the bounds to: 0 to 3.
Thus we have:
(2u5/2)/5-(2u3/2) from 0 to 3.
Thus I get: -4.15.
However the correct answer is positive 4.15.
I know the answer should be positive but what I don't understand is why I'm getting a negative answer. Please help.
Thanks in advance.