Integrating Annoying Trig Integral: Help Appreciated

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SUMMARY

The integral I = ∫₀²π (1/(1 + e cos θ)³) dθ, where 0 < e < 1, can be evaluated using a conformal transformation. By applying the transformation z = exp(iθ), the integral is converted to a contour integral over the unit circle in the complex plane. The resulting expression is dz/(i z) * 1/[1 + e(z + z^(-1))/2]³. To solve this, one must simplify the fraction and analyze the poles within the unit circle for a definitive result.

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Hi...would appreciate any suggestions re the following integral which has appeared in a celestial-mechanics calculation:

[tex]I = \int_0^{2\pi } {\frac{1}{{(1 + e\cos \theta )^3}}d\theta }[/tex]

where [tex]0 < e < 1[/tex].

Integration by parts seems a sensible approach but for some reason I can't get sensible results. I presume I'm making some idiotic mistake that I'm just not picking up when I check my calculations (frustrating as hell!). I'm pretty sure there is supposed to be a fairly neat result but MATLAB and Mathematica aren't giving me anything.

Any ideas? Thanks in advance.
 
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Apply the conformal transform z = exp(i theta). Then the integral becomes the integral over the unit circle in the complex plane of:


dz/(i z) 1/[1+e (z+z^(-1))/2]^3

Simplify the fraction and consider the poles that are inside the unit circle.
 
Thank you!
 

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