Integrating cos²x with integration by parts

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i want someone to help me with the integral of cosX^2



i attempted using integrals by parts.. wat i got when i differentiate it i didn't go back to the same integral equation.
is it that it is not possible??
 
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evra said:
i want someone to help me with the integral of cosX^2

I'm not sure what you mean here. If you want to take the integral of [tex]\cos x^2[/tex], then this cannot be solved through ordinary methods. However, if you want to solve (cosx)^2, just apply the half-angle formula.
 
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hi evra! :smile:
evra said:
i attempted using integrals by parts.. wat i got when i differentiate it i didn't go back to the same integral equation.
is it that it is not possible??

∫ cosx.cosx dx

= [sinx.cosx] + ∫sinx.sinx dx

= [sinx.cosx] + ∫ 1 dx - ∫cosx.cosx dx​

so 2∫ cosx.cosx dx = [sinx.cosx] + ∫ 1 dx :wink:

(or just use one of the standard trignonometric identites as gb7nash :smile: says)
 


mr gb7nash, yes i mean ∫cos x^2. but the relation u used above can't work. i tried it but the rsult i got when i defferentiate it i can't come back to the original answer.
please check it.
 
evra said:
i tried it but the rsult i got when i defferentiate it i can't come back to the original answer.
please check it.

nooo … you show us what you got :wink:
 


i got sinX^2 and when I differentiate this I got 2XcosX^2
 
evra said:
i got sinX^2 and when I differentiate this I got 2XcosX^2

(try using the X2 icon just above the Reply box :wink:)

no, if you want to find ∫ cos(x2) dx, then as gb7nash said, this cannot be solved through ordinary methods …

integration by parts, or the half-angle formula, will only work for ∫ cos2x dx :wink:
 


then its not possible... thanks! its like sinX^2.
BUT why is it that its not possible.. what are the prooves? a younger brother is bordering me with it and he said i should give him concret mathematical proves.
thanks
 


evra said:
then its not possible... thanks! its like sinX^2.
BUT why is it that its not possible.. what are the prooves? a younger brother is bordering me with it and he said i should give him concret mathematical proves.
thanks

It's possible with an infinite series expansion of sin(A), A=x^2
 


no i don't think so because i did that and if i defferentiate the answer i got, i can't get back to sin(x2)