Integrating ∫cos(x)^2*tan(x)^3dx using u-substitution and integration by parts

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SUMMARY

The integral ∫cos(x)^2*tan(x)^3dx can be approached using u-substitution and integration by parts. The integrand simplifies to ∫(sin^3(x)/cos(x))dx, which can further be expressed as ∫(sin(x)(1-cos^2(x)))dx. This transformation allows for the application of integration techniques, leading to a more manageable integral that can be solved effectively.

PREREQUISITES
  • Understanding of u-substitution in calculus
  • Familiarity with integration by parts
  • Knowledge of trigonometric identities, specifically sin(x) and cos(x)
  • Ability to manipulate integrals involving trigonometric functions
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  • Practice solving integrals using u-substitution with trigonometric functions
  • Explore advanced integration techniques, including integration by parts
  • Study trigonometric identities and their applications in calculus
  • Work on problems involving the simplification of complex integrands
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Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for examples of integrating trigonometric functions using u-substitution and integration by parts.

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Homework Statement


∫cos(x)^2*tan(x)^3dx

Homework Equations


The Attempt at a Solution



Were learning Integration by parts and u substitution but this one I can't figure out. I tried making it ∫cos(x)*(sin(x)^3)/(cos(x)^3)dx and then ∫tan(x)*sin(x)^2 but I don't know if I'm going in the right direction because I don't know how to solve from here.
 
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NWeid1 said:

Homework Statement


∫cos(x)^2*tan(x)^3dx

Homework Equations



The Attempt at a Solution



Were learning Integration by parts and u substitution but this one I can't figure out. I tried making it ∫(cos(x))^2*(sin(x)^3)/(cos(x)^3)dx and then ∫tan(x)*sin(x)^2 but I don't know if I'm going in the right direction because I don't know how to solve from here.
That should be [itex]\displaystyle \int\frac{\cos^2(x)\sin^3(x)}{\cos^3(x)}\,dx[/itex]

The integrand can be simplified to:
[itex]\displaystyle \frac{\sin^3(x)}{\cos(x)}[/itex]​
Then change sin3(x) to (sin(x))(1-cos2(x))

The integrand becomes:
[itex]\displaystyle \frac{\sin(x)}{\cos(x)}-\sin(x)\cos(x)[/itex]​
 

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