Integrating e^(-3x) with u-Substitution

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SUMMARY

The integral of the function e^(-3x) / (1 + e^(-3x)) can be solved using u-substitution. By letting u = 1 + e^(-3x), the differential du is calculated as -3e^(-3x) dx, leading to the substitution du/3 = e^(-3x) dx. The final result of the integration is -1/3 ln|1 + e^(-3x)| + C, confirming the correct application of u-substitution in this context.

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Homework Statement



before we start, i don't know how to do the integral sign, so we'll use [

I need to integrate
[ e^(-3x) / 1 + e^(-3x)



Homework Equations



I've always had trouble with doing integration with e

The Attempt at a Solution



I used u=1+e^(-3x)
du = -3e^(-3x)

so du/3 = e^(-3x)

I then do

(1/-3) [ u and i end up with the answer 1/-3 (1+e^(-3x)) + c


answer that i am supposed to get is

-1/3ln|1 + e^(-3x)| + C
 
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nevermind, stupid post. i got it.. :D
 

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