hiyum
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\[ y'=-y+e^{(-2)t} \]
As in the other thread:hiyum said:\[ y'=-y+e^{(-2)t} \]
Though you could try the integrating factor approach as I showed you in the other Forum.topsquark said:As in the other thread:
[math]y' + y = e^{-2t}[/math]
How do you find the integrating factor here?
-Dan